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求助：x²+y²/ x²+2xy+y²+2/xy÷（1/x+1/y）²

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求助：x²+y²/ x²+2xy+y²+2/xy÷（1/x+1/y）²化简
求助：x²+y²/ x²+2xy+y²+2/xy÷（1/x+1/y）²
=(x²+y²)/(x+y)²+(2/xy)÷[(x+y)²/x²y²]
=(x²+y²)/(x+y)²+(2/xy)×[x²y²/(x+y)²]
=(x²+y²)/(x+y)²+2xy/(x+y)²
=(x²+2xy+y²)/(x+y)²
=(x+y)²/(x+y)²
=1
1-x²+2xy-y² 计算:(1).(-2xy²)*(3x²y)² x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 越快越好（1）(xy²+3)(xy²+3)-2x(-x+y)（2）(x+2)(x²+4)( (x+y-2xy)(x+y-2)+(1-xy)² x³y³-x²y²-xy+1 方程组{x²+y²=10(1)x²-3xy+2y²=0(2)怎么解 先化简,再求值：（x²）/（x²-2xy+y²）÷（x²+2xy+y²）/（x& 3x²-4xy+y² ①先化简,再求值.4（3x²y—1/2xy²）—5（—xy²+3x²y）,其中x 因式分解 x²-3xy+2y²+x-2 (x+2y)²-x²-2xy