carl has $9 more than david does.hilbert has 1/3 of the amou

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carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?

Let $x be the amount of Carl has,$(x-9) be the amount of David has and $(x/3) be the amount of Hibert.
x+(x-9)+(x/3)=61
7x-27=183
7x=210
x=30
Carl has $30,David has $21 and Hibert has $10

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