Sum It UpGiven a specified total t and a list of n integers,
来源:学生作业帮 编辑:百度作业网作业帮 分类:综合作业 时间:2024/08/16 19:40:34
Sum It Up
Given a specified total t and a list of n integers,find all distinct sums using numbers from the list that add up to t.For example,if t = 4,n = 6,and the list is [4,3,2,2,1,1],then there are four different sums that equal 4:4,3+1,2+2,and 2+1+1.(A number can be used within a sum as many times as it appears in the list,and a single number counts as a sum.) Your job is to solve this problem in general.
Input
The input file will contain one or more test cases,one per line.Each test case contains t,the total,followed by n,the number of integers in the list,followed by n integers x 1 ,...,x n .If n = 0 it signals the end of the input; otherwise,t will be a positive integer less than 1000,n will be an integer between 1 and 12 (inclusive),and x 1 ,...,x n will be positive integers less than 100.All numbers will be separated by exactly one space.The numbers in each list appear in nonincreasing order,and there may be repetitions.
Output
For each test case,first output a line containing `Sums of',the total,and a colon.Then output each sum,one per line; if there are no sums,output the line `NONE'.The numbers within each sum must appear in nonincreasing order.A number may be repeated in the sum as many times as it was repeated in the original list.The sums themselves must be sorted in decreasing order based on the numbers appearing in the sum.In other words,the sums must be sorted by their first number; sums with the same first number must be sorted by their second number; sums with the same first two numbers must be sorted by their third number; and so on.Within each test case,all sums must be distinct; the same sum cannot appear twice.
Sample Input
4 6 4 3 2 2 1 1
5 3 2 1 1
400 12 50 50 50 50 50 50 25 25 25 25 25 25
0 0
Sample Output
Sums of 4:
4
3+1
2+2
2+1+1
Sums of 5:
NONE
Sums of 400:
50+50+50+50+50+50+25+25+25+25
50+50+50+50+50+25+25+25+25+25+25
用C/C++写程序,
Given a specified total t and a list of n integers,find all distinct sums using numbers from the list that add up to t.For example,if t = 4,n = 6,and the list is [4,3,2,2,1,1],then there are four different sums that equal 4:4,3+1,2+2,and 2+1+1.(A number can be used within a sum as many times as it appears in the list,and a single number counts as a sum.) Your job is to solve this problem in general.
Input
The input file will contain one or more test cases,one per line.Each test case contains t,the total,followed by n,the number of integers in the list,followed by n integers x 1 ,...,x n .If n = 0 it signals the end of the input; otherwise,t will be a positive integer less than 1000,n will be an integer between 1 and 12 (inclusive),and x 1 ,...,x n will be positive integers less than 100.All numbers will be separated by exactly one space.The numbers in each list appear in nonincreasing order,and there may be repetitions.
Output
For each test case,first output a line containing `Sums of',the total,and a colon.Then output each sum,one per line; if there are no sums,output the line `NONE'.The numbers within each sum must appear in nonincreasing order.A number may be repeated in the sum as many times as it was repeated in the original list.The sums themselves must be sorted in decreasing order based on the numbers appearing in the sum.In other words,the sums must be sorted by their first number; sums with the same first number must be sorted by their second number; sums with the same first two numbers must be sorted by their third number; and so on.Within each test case,all sums must be distinct; the same sum cannot appear twice.
Sample Input
4 6 4 3 2 2 1 1
5 3 2 1 1
400 12 50 50 50 50 50 50 25 25 25 25 25 25
0 0
Sample Output
Sums of 4:
4
3+1
2+2
2+1+1
Sums of 5:
NONE
Sums of 400:
50+50+50+50+50+50+25+25+25+25
50+50+50+50+50+25+25+25+25+25+25
用C/C++写程序,
#include
#include
int num[13];
int x[13];
int sum,n;
int cw;
int result[1000][13];
int count;
void backtrack(int t)
{
if(t>n)
{
if(cw==sum)
{
int i;
for(i=1;i
#include
int num[13];
int x[13];
int sum,n;
int cw;
int result[1000][13];
int count;
void backtrack(int t)
{
if(t>n)
{
if(cw==sum)
{
int i;
for(i=1;i
Sum It UpGiven a specified total t and a list of n integers,
7、The sum of n different positive integers is less than 50.T
Find the sum of all the integers N > 1 with the properties t
a total sum 的用法
问道sat数学题The median of a list of 99 consecutive integers is 6
the sum of the first n odd integers
一道英语数学题A the sum of the three greatest distinct integers tha
看不懂题干.The sum of 4 integers is even.Which one is larger,A or
英语翻译5、Three positive integers have a sum of 28.The greatest
1.Three positive integers have a sum of 28.The greatest poss
这道数学题怎么做啊If the sum of three different positive integers a,
1、three positive integers(正整数)have a sum of 28.The greatest