X-1分之X -1等于X²+X-2

X-X/2=15方程两边同乘以2得：2X-X=30X=30如果原题X-2是整体做为分母的话：X/(X-2)=15方程两边同乘以X-2得：X=15(X-2)X=15X-3030=15X-X14X=30X

x=0可以先提一个X出来得到x（1/X-1-1/x-2）=0当x=0或x-1=x-2时成立显然后者不成立所以x=0

x+1分之x+2加上x+4分之x+5等于x+2分之x+3加上x+3分之x+4x+x/1+2+x+x/4+5=x+x/2+3+x+x/3+4x+x+2+x+x/4+5=x+x/2+3+x+x/3+4x+

x2-(x+2)(x-2)-(x+x分之一)2=x2-x2+4-x2-1/x2-2=-x2+2-1/x2=-(x2-2+1/x2)=-(x-1/x)2

(x+1)/(x^2-x)-1/3x=(x+5)/(3x-3)3(x+1)/(x^2-x)-1/x=(x+5)/(x-1)3(x+1)-(x-1)=x(x+5)3x+3-x+1=x^2+5x2x+4=

x+3分之x+x平方-9分之6等于x-3分之1两边乘（x+3）（x-3）x(x-3)+6=x+3x²-3x+6=x+3x²-4x+3=0(x-3)(x-1)=0x1=3x2=1由于

若x加x分之1等于15,则x-x分之1等于多少?x+1/x=15x=15-1/x把x=15-1/x代入：x-1/x=15-1/x-1/x=15记得采纳哦!

解分式方程输入很辛苦.经检验X=7/2是原方程的解.

=[(x+3)-(x+2)]/(x+2)(x+3)+[(x+4)-(x+3)]/(x+3)(x+4)+[(x+5)-(x+4)]/(x+5)(x+4)=1/(x+2)-1/(x+3)+1/(x+3)-

由x²-x+1分之x等于2得：x分之x²-x+1等于2分之1即：x-1+1/x=1/2x+1/x=3/2(x+1/x)^2=9/4x^2+2+1/x^2=9/4x^2+1+1/x^

(x/2)+(x/6)+(x/12)+(x/20)+(x/30)+(x/42)=x/(1*2)+x/(2*3)+x/(3*4)+x/(4*5)+x/(5*6)+x/(6*7)=x-x/2+x/2-x/

(x-1)/3-(x+2)/6=(4-x)/2等式两边同乘6得：2(x-1)-(x+2)=3(4-x)去括号：2x-2-x-2=12-3x移项：4x=16x=4

(x^2-1)/2-(x-2)/3=x^23x^2-3-2(x-2)=6x^23x^2-3-2x+4=6x^23x^2+2x-1=0(3x-1)(x+1)=0所以x=1/3或x=-1

x^2/(x-1)-x+1=x^2/(x-1)-(x^2-x)/(x-1)+(x-1)/(x-1)=（x^2-x^2+x+x-1)/(x-1)=(2x-1)/(x-1）希望能对你有所帮助有不会的可以继

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=

(x-1)(x-3)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-5)=(x-1)(x-2)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-4)(x-1)(x-3)(x-5)(x

x/(x-2)=(x-4)/(x-5)方程两边同乘(x-2)(x-5),得:x(x-5)=(x-4)(x-2)x^2-5x=x^2-6x+8x=8x/(x-3)=(x+1)/(x-1)x^2-x=x^

X=1/X,等式两边都乘以X,则X²=1解得X=±1由于x的绝对值等于-x,说明X不是正数,则X=-1

|x|/x=-1,x在分母x≠0那么|x|=-x∴x