②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/09 17:13:14
②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π-α)求①化简f(α)②若cos(α-3/2π)=1/5求f(α)的值③若α=-1860°求f(α)的值
![②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π](/uploads/image/z/165647-47-7.jpg?t=%E2%91%A1%E8%8B%A5cos%EF%BC%88%E5%B7%B2%E7%9F%A5%CE%B1%E6%98%AF%E7%AC%AC%E4%B8%89%E8%B1%A1%E9%99%90%E8%A7%92f%28%CE%B1%29%3Dsin%28%CF%80-%CE%B1%29cos%282%CF%80-%CE%B1%29tan%28-%CE%B1-%CF%80%29%2Ftan%EF%BC%88-%CE%B1%EF%BC%89sin%EF%BC%88-%CF%80)
f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π-α)
=sinα * cosα * (-tanα) /[(-tanα)*sinα]
=cosα
cos(α-3/2 π)=-cosα=1/5
f(α)=cosα=-1/5
f(-1860°)=cos(-1860°)=cos(1860°)=cos(10*180°+60)=cos60°=1/2
=sinα * cosα * (-tanα) /[(-tanα)*sinα]
=cosα
cos(α-3/2 π)=-cosα=1/5
f(α)=cosα=-1/5
f(-1860°)=cos(-1860°)=cos(1860°)=cos(10*180°+60)=cos60°=1/2
②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π
已知f(α)=sin(π-α)cos(2π-α)tan(π-α)/-tan(-π-α)sin(-π-α),若α是第三象限
已知α是第三象限角,且f(α)=[sin(π+α)cos(2π-α)tan(-α+3π/2)tan(-α-π)]/sin
已知α是第三象限角,f(α)=[sin(π-a)cos(2π-a)tan(1.5π-a)tan(-a-π)]/sin(-
α是第三象限角,f(α)={sin(α-π/2)cos(3π/2+α)tan(π-α)}/{tan(-α-π)sin(-
已知α是第三象限角,且f(α)=sin(π-α)cos(2π-α)tan(-α+3π/2)/cos(-α -π) (1)
已知α为第三象限角,且f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)tan(2π-α)
已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)求①化简f(α)
已知f=[sin(π-α)cos(2π-α)tan(-π-α)]/sin(-π-α),⑴化简f(a)、⑵若α是第三象限,
已知tanα=2 若α是第三象限角,求sin(kπ-α)+cos(kπ+α)(k∈z)的值
已知α是第三象限角,且f(α)=[sin(α-π/2)cos(3π/2+α)tan(π-α)]/[tan( -α-π)s
1.已知α是第二象限角,f(α)=[sin(3π/2-α)·cos(2π-α)·tan(π-α)]/-cos(-π-α)