设函数f(θ)=-1/2+(sin5θ/2)/(2sinθ/2),0
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/17 00:58:58
设函数f(θ)=-1/2+(sin5θ/2)/(2sinθ/2),0
![设函数f(θ)=-1/2+(sin5θ/2)/(2sinθ/2),0](/uploads/image/z/19237203-27-3.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28%CE%B8%29%3D-1%2F2%2B%28sin5%CE%B8%2F2%29%2F%282sin%CE%B8%2F2%29%2C0)
1.f(θ)=-1/2+(sin5θ/2)/(2sinθ/2)=-1/2+[sin(2θ)cos(θ/2)+cos(2θ)sin(θ/2)]/[2sin(θ/2)]
=-1/2+cos(2θ)/2+[2sinθcosθcos(θ/2)]/[2sin(θ/2)]
=-1/2+cos(2θ)/2+2cosθ[cos(θ/2)]^2=-1/2+[2(cosθ)^2-1]/2+cosθ(cosθ+1)
=2(cosθ)^2+cosθ-1 (0
=-1/2+cos(2θ)/2+[2sinθcosθcos(θ/2)]/[2sin(θ/2)]
=-1/2+cos(2θ)/2+2cosθ[cos(θ/2)]^2=-1/2+[2(cosθ)^2-1]/2+cosθ(cosθ+1)
=2(cosθ)^2+cosθ-1 (0
设函数f(θ)=(2sinθcosθ+2.5)/(sinθ+cosθ),θ∈【0,派/2】,求函数f(θ)的最小值
设函数f(x)=sin(2x+φ)(0
设函数f(x)=sin(2x+a)(0
设函数f(x)=sin(2x+φ)(-π
设函数 f(x)=sin(2x+y),(-π
设函数f x=SIN(2X+φ)(-π
设函数f(x)=sin(2x+ φ)(-π
设函数f(x)=sin(wx+t)(-π/2
设函数f(x)=sin(1/2x+φ)(0
★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ]
设函数f(x)=x³+x,若当0≤θ≤π/2时,f(msinθ)+f(sinθ-sin²θ-2)<0
高一数学函数已知函数f(x)=2sinθcosx-2sinθ