main(){ int a[3][3]={1,2,3,4,5,6,7,8,9},m,k,t; for (m=0;m
main(){ int a[3][3]={1,2,3,4,5,6,7,8,9},m,k,t; for (m=0;m
#include "stdio.h" main() { int m,n; float k; for (m=6;m>2;m
(5)main( ) { int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; for(k=0
#include main() { int k,j,m; for(k=5;k>=1;k--) { m=0; for(j=
#include void main() { int m; for(m=10;m>3.m--) {if(m%3) m--
31、下列程序段中可实现1×2×3×4×5×6×7×8×9×10的是( ).A、int k=1,m=0; for(;k
main() { int i,mum,m int b[8]={3,5,6,10,0,123.100.-9}} ; m=b
#include #define S(x) x*x main() {int a=9,k=3,m=2; a/=S(k+m)
main() {int m[10],a;for(a=0,a
#include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k
#include main() { int a=1,b=2,c=3,d=4,m=5,n=6; a=(m=a>b)&&(n
#include main() { int m,i,k; scanf("%d",&m); k=sqrt(m); for(