y=f(sin²x)+sinf²(x)求dy/dx
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y=f(sin²x)+sinf²(x)求dy/dx
设f(u)是可导函数
设f(u)是可导函数
![y=f(sin²x)+sinf²(x)求dy/dx](/uploads/image/z/2087215-7-5.jpg?t=y%3Df%28sin%26%23178%3Bx%29%2Bsinf%26%23178%3B%28x%29%E6%B1%82dy%2Fdx)
使用复合求导法则
dy/dx=
整理一下即可.
dy/dx=
![](http://img.wesiedu.com/upload/e/99/e99b9fd469e74e3856bf2cdf64d6cfb0.jpg)
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