3x+4y+z=14 x+5y+2z=11 2x+2y-z=3 x-y=7 5x+2y=8 解方程
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3x+4y+z=14 x+5y+2z=11 2x+2y-z=3 x-y=7 5x+2y=8 解方程
3x+4y+z=14 ①
x+5y+2z=11 ②
2x+2y-z=3③
①*2-②
6x+8y+2z-x-5y-2z=28-11
5x+3y=17④
①+③
3x+4y+z-2x-2y-z=14+11
x+2y=25⑤
由⑤得:x=25-2y 代入④
5*(25-2y)+3y=17
125-10y+3y=17
-7y=17-125
-7y=-108
y=6
x=25-2*6=25-12=13
x-y=7①
5x+2y=8②
由①得:x=7+y 代入②
5*(7+y)+2y=8
35+5y+2y=8
7y=-27
y=-27/7
x+27/7=7
x=7-27/7
x=22/7
x+5y+2z=11 ②
2x+2y-z=3③
①*2-②
6x+8y+2z-x-5y-2z=28-11
5x+3y=17④
①+③
3x+4y+z-2x-2y-z=14+11
x+2y=25⑤
由⑤得:x=25-2y 代入④
5*(25-2y)+3y=17
125-10y+3y=17
-7y=17-125
-7y=-108
y=6
x=25-2*6=25-12=13
x-y=7①
5x+2y=8②
由①得:x=7+y 代入②
5*(7+y)+2y=8
35+5y+2y=8
7y=-27
y=-27/7
x+27/7=7
x=7-27/7
x=22/7
x/2=y/3=z/5 x+3y-z/x-3y+z
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y
解方程:{2x+3y+z=7,x+y+z=4,3x+y-z=-4
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
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