百度作业网matlab用for程序10*10的矩阵中哪个最小的元素
来源：学生作业帮 编辑：百度作业网作业帮 分类：综合作业 时间：2024/07/31 08:24:51
matlab用for程序10*10的矩阵中哪个最小的元素
可以不用for循环啊,很简单的,方法如下：
>>a=rand(10)
a =
0.8147 0.1576 0.6557 0.7060 0.4387 0.2760 0.7513 0.8407 0.3517 0.0759
0.9058 0.9706 0.0357 0.0318 0.3816 0.6797 0.2551 0.2543 0.8308 0.0540
0.1270 0.9572 0.8491 0.2769 0.7655 0.6551 0.5060 0.8143 0.5853 0.5308
0.9134 0.4854 0.9340 0.0462 0.7952 0.1626 0.6991 0.2435 0.5497 0.7792
0.6324 0.8003 0.6787 0.0971 0.1869 0.1190 0.8909 0.9293 0.9172 0.9340
0.0975 0.1419 0.7577 0.8235 0.4898 0.4984 0.9593 0.3500 0.2858 0.1299
0.2785 0.4218 0.7431 0.6948 0.4456 0.9597 0.5472 0.1966 0.7572 0.5688
0.5469 0.9157 0.3922 0.3171 0.6463 0.3404 0.1386 0.2511 0.7537 0.4694
0.9575 0.7922 0.6555 0.9502 0.7094 0.5853 0.1493 0.6160 0.3804 0.0119
0.9649 0.9595 0.1712 0.0344 0.7547 0.2238 0.2575 0.4733 0.5678 0.3371
>>[a_max I]=max(a(:))
a_max =
0.9706
I =
12
>>[i j]=ind2sub(size(a),12)
i =
2
j =
2
>>a=rand(10)
a =
0.8147 0.1576 0.6557 0.7060 0.4387 0.2760 0.7513 0.8407 0.3517 0.0759
0.9058 0.9706 0.0357 0.0318 0.3816 0.6797 0.2551 0.2543 0.8308 0.0540
0.1270 0.9572 0.8491 0.2769 0.7655 0.6551 0.5060 0.8143 0.5853 0.5308
0.9134 0.4854 0.9340 0.0462 0.7952 0.1626 0.6991 0.2435 0.5497 0.7792
0.6324 0.8003 0.6787 0.0971 0.1869 0.1190 0.8909 0.9293 0.9172 0.9340
0.0975 0.1419 0.7577 0.8235 0.4898 0.4984 0.9593 0.3500 0.2858 0.1299
0.2785 0.4218 0.7431 0.6948 0.4456 0.9597 0.5472 0.1966 0.7572 0.5688
0.5469 0.9157 0.3922 0.3171 0.6463 0.3404 0.1386 0.2511 0.7537 0.4694
0.9575 0.7922 0.6555 0.9502 0.7094 0.5853 0.1493 0.6160 0.3804 0.0119
0.9649 0.9595 0.1712 0.0344 0.7547 0.2238 0.2575 0.4733 0.5678 0.3371
>>[a_max I]=max(a(:))
a_max =
0.9706
I =
12
>>[i j]=ind2sub(size(a),12)
i =
2
j =
2