log8 4=?2^(log2 3-2)=?
log8 4=?2^(log2 3-2)=?
(log8 9/log2 3)=?
你说lo5*lo8=3 log8(2)*log2(64) 依你的算法是log8(2)*4=1*log4(64)=3 你认
log8 (log2 4根号2)的值
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(
已知log2^3=a.则log8^3= log8^9=
log8的9次方/log2的3次方=
对数的平方如何算?log8^9=log2^3^3^2是怎么得来的?
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?
我想知道为什么 log(2^2) 3=1/2*log2 3 log8 3=log(2^3) 3=1/3*log2 3
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^
(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32