有三道二次根式的题,速解,
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/08/10 09:56:46
有三道二次根式的题,速解,
![](http://img.wesiedu.com/upload/9/b0/9b0d50d68a4eb8b04ab883da8c092f17.jpg)
![](http://img.wesiedu.com/upload/5/69/569d884ed6d13d5523001a77a26af0c0.jpg)
![](http://img.wesiedu.com/upload/6/40/640a5362d7b26e06ba8b23bc09a0118a.jpg)
第一道是化简题,后两道是计算题
![](http://img.wesiedu.com/upload/9/b0/9b0d50d68a4eb8b04ab883da8c092f17.jpg)
![](http://img.wesiedu.com/upload/5/69/569d884ed6d13d5523001a77a26af0c0.jpg)
![](http://img.wesiedu.com/upload/6/40/640a5362d7b26e06ba8b23bc09a0118a.jpg)
第一道是化简题,后两道是计算题
![有三道二次根式的题,速解,](/uploads/image/z/3002847-15-7.jpg?t=%E6%9C%89%E4%B8%89%E9%81%93%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%E7%9A%84%E9%A2%98%2C%E9%80%9F%E8%A7%A3%2C)
(5√2+2√3)/(5+√6)+(3-√3)/(√3-1)-(4-2√2)/(√2-1)
=√2(5+√6)/(5+√6)+√3(√3-1)/(√3-1)-2√2(√2-1)/ (√2-1)
=√2+√3-2√2
=√3-√2
=((1+√(1-x²))/√(1+x))/(1+√(1-x²)
=1/√(1+x)
=√(1+x) /(1+x)
=√((x²-y²)((x²)²-(y²)²))=√((x²-y²)(x²-y²) (x²+y²))
=√((x²-y²)²(x²+y²))
=(x²-y²)√( (x²+y²))
=√2(5+√6)/(5+√6)+√3(√3-1)/(√3-1)-2√2(√2-1)/ (√2-1)
=√2+√3-2√2
=√3-√2
=((1+√(1-x²))/√(1+x))/(1+√(1-x²)
=1/√(1+x)
=√(1+x) /(1+x)
=√((x²-y²)((x²)²-(y²)²))=√((x²-y²)(x²-y²) (x²+y²))
=√((x²-y²)²(x²+y²))
=(x²-y²)√( (x²+y²))