(1) [(-1/3)x²y][(3/4)y²-(1/2)x+(1/3)]
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/31 03:25:06
(1) [(-1/3)x²y][(3/4)y²-(1/2)x+(1/3)]
(2) 12x²y[(-2/3)x²-(5/6)xy+(3/4)y²]
(3) (4x²-y²)[(2x+y)²-(2x-y)²]
注:“/”是分数线,1/2是二分之一
(2) 12x²y[(-2/3)x²-(5/6)xy+(3/4)y²]
(3) (4x²-y²)[(2x+y)²-(2x-y)²]
注:“/”是分数线,1/2是二分之一
![(1) [(-1/3)x²y][(3/4)y²-(1/2)x+(1/3)]](/uploads/image/z/3093501-21-1.jpg?t=%EF%BC%881%EF%BC%89+%5B%EF%BC%88-1%2F3%29x%26sup2%3By%5D%5B%283%2F4%29y%26sup2%3B-%281%2F2%29x%2B%281%2F3%29%5D)
(1)= (-1/4)x2y3+1/6x3y -1/9x2y (2)=(-8)x4y -10x3y2 +9x2y3 (3)=(4x2-y2)(2x+y+2x-y)(2x+y-2x+y) = (4x2-y2)8xy =32x3y -8xy3 注;x2 意思是x的平方
计算:(1).(-2xy²)*(3x²y)²
再求代数式(4x²-7x+6y-1)-(-2x²+3y²+2y+2x)+(-6x²
已知:多项式(2mx²-x²+3x-1)-(5x²-4y²+3x²)不
(1) [(-1/3)x²y][(3/4)y²-(1/2)x+(1/3)]
已知方程x²+y²-2(m+3)+2(1-4m²)+(4m²)²+9=
y=(x²+1)²/[(3x²+2)(2x²+3)],求最小值
越快越好(1)(xy²+3)(xy²+3)-2x(-x+y)(2)(x+2)(x²+4)(
1、若|x-1|+(y+3)²=0,则x²+y²=
已知关于x的多项式(2mx²-x²+3x+1)-(5x²-4y²+3x)不含x&
①先化简,再求值.4(3x²y—1/2xy²)—5(—xy²+3x²y),其中x
1 3x²+4xy-y²=
(2mx²-x²+3x+1)-(5x²+4y²+3x)的值与x无关,求2m&su