设x=2.5 a=7 c=4.7,算术表达式x+a%3*(int)(x+y)%2/4的值是?
设x=2.5 a=7 c=4.7,算术表达式x+a%3*(int)(x+y)%2/4的值是?
求算术表达式x+a%3*(int)(x+y)%2/4的值,设x=2.5,a=7,y=4.7中a%3*(int)(x+y)
已知:a=7,x=2.5,y=4.7(a整型,x,y浮点),计算算术表达式x+a%3*(int)(x+y)%2/4的值.
(float)(a+b)/2+(int)x%(int)y 设a=2,b=3,x=3.5,y=2.5 求算术表达式的值
C语言中的算数表达式设x=2.5,a=7,y=4.7 则x+a%3*(int)(x+y)%2/4的值为多少?
设X=2.5,a=7,y=4.7,表达式x+a%3*(int)(x+y)%2/4的值是?
若有定义:int a=7;float x=2.5,y=4.7; ,则表达式x+a%3*(int)(x+y)%2/4的值是
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若有定义:int a=7;float x=2.5,y=4.7;则表达式x+a%3*(int)(x+y)%2/4的值是?
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