因式分解,4x^2 2xy-2y^2-11x 7y-3
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因式分解,4x^2 2xy-2y^2-11x 7y-3
![因式分解,4x^2 2xy-2y^2-11x 7y-3](/uploads/image/z/3555886-22-6.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%2C4x%5E2+2xy-2y%5E2-11x+7y-3)
答:加号不见了:
4x^2+2xy-2y^2-11x+7y-3=0
看成是关于x的方程
判别式=(2y-11)^2-4*4*(-2y^2+7y-3)
=4y^2-44y+121+32y^2-112y+48
=36y^2-156y+169
=(6y-13)^2
x=[-(2y-11)±√(6y-13)^2]/(2*4)
x1=(2y-1)/4,x2=-y+3
所以:
4x^2+2xy-2y^2-11x+7y-3
=4*[x-(2y-1)/4]*[x-(3-y)]
=(4x-2y+1)(x+y-3)
4x^2+2xy-2y^2-11x+7y-3=0
看成是关于x的方程
判别式=(2y-11)^2-4*4*(-2y^2+7y-3)
=4y^2-44y+121+32y^2-112y+48
=36y^2-156y+169
=(6y-13)^2
x=[-(2y-11)±√(6y-13)^2]/(2*4)
x1=(2y-1)/4,x2=-y+3
所以:
4x^2+2xy-2y^2-11x+7y-3
=4*[x-(2y-1)/4]*[x-(3-y)]
=(4x-2y+1)(x+y-3)