lim 2n-根号(3-an+4n^2)=1,则a为
lim 2n-根号(3-an+4n^2)=1,则a为
lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b
a,b为常数.lim(n->无穷)an^2+bn+2/2n-1=3 求a,b
lim[{根号(n^2+an)}-(bn+1)]=b,求a
若lim(2n-√4n^2+an+3)=1,n→∞,求a.
数列极限(n为无限大)lim(n+1-根号(n^2+n))=
lim[2n+(an^2-2n+1)/(bn+2)]=1,则点(a,b)坐标为
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
lim根号n^2+n+1/3n-2
若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b
数列an中,an=1/(根号(n+2)+根号n),则an的前n项和为