化简cos(2π/3-x)+cos(2π/3+x)+cosx
化简cos(2π/3-x)+cos(2π/3+x)+cosx
化简:1.【(sin^2)(-X-π) *cos(π+X)cosX】/【tan(2π+X) *(cos^3 (-X-π)
化简2sinx*cosx*cos(2π-x)+cos(π+2x)*cosx*tanx
cosx+根号3sinx=2cos(x-π/3)
已知函数f(x)=cos(2x-π/3)+(cosx+sinx)(cosx-sinx)
f(x)=2cos(2x+π/3)+√3(sinx+cosx)^2 化简
1.化简f(x)=cosx(asinx-cosx)+cos(π/2-x)cos(π/2-x).2.化简f(x)=4cos
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知sinx+cosx/sinx-cosx=2,求2cos(π-x)-3sin(π+x)/4cos(-x)+sin(2π
sin(x+1/2π)=cosx?还是cos-x
cos(x)cos(2x)=[cosx+cos(3x)]/2 大神们求步骤啊,灰常感谢
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x