∑(2n-3)!/(2n)!2≤n

证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n ∑(2n-3)!/(2n)!2≤n [3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简 -n^3+8n^2-16n 化简(n+1)(n+2)(n+3) 2^n/n*(n+1) lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 计算：n(n+1)(n+2)(n+3)+1 (1/(n^2 n 1 ) 2/(n^2 n 2) 3/(n^2 n 3) ……n/(n^2 n n)) 当N越于无穷大 当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3).. 1 + (n + 1) + n*(n + 1) + n*n + (n + 1) + 1 = 2n^2 + 3n + 3 n是自然数,0≤n≤101,则| n-1|+|n-2|+|n-3|+…+|n-100|的最小值,