若|y+5|+(5x+1)^2=0,求-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
x^8-x^7y+x^6y^2-x^5y^3+x^4y^4-x^3y^5+x^2y^-xy^7+y^8
若|y+5|+(5x+1)^2=0,求-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
若|y+5|+(5x+1)^2=0,求代数式-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4
若2x-3y=0,求5x+4y/3x-2y
若x^5+x^4y+x^4+x+y+1=0,且3x+2y=1,求x,y的值
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai