int sum=0,x=5;do[sum+=x;]while(!--x)最终sum值是多少?
int sum=0,x=5;do[sum+=x;]while(!--x)最终sum值是多少?
int i=0,sum=1; do{sum+=i++;} while(i
sum+=x%2?x:
void func(char *s) { int sum = 0; while(*s) sum += (*s++ - 9
main() { double x,n,sum=0; scanf("%lf",&n); if (((int)n%2)!=
C语言从1加到100#include main(){int i,sum;i=1,sum=0;while(i++
"sum="+sum" odd"+odd
matlab中x(:,i)=x(:,i)/sum(x(:,
VB编程 Dim sum As Double,x As Double sum = 0 x = 0 For i = 1 T
matlab里边这个sum(X,1),sum(X,
while语句问题.#include #include int main (void){int i,sum=0;puts
sum(x,y,