化简:√3 sin〖(6/π〗-α)-cos〖(6/π〗-α)
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化简:√3 sin〖(6/π〗-α)-cos〖(6/π〗-α)
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√3 sin (π/6-α)-cos(π/6 -α)
=2[√3/1sin (π/6-α) -1/2cos(π/6-α)]
=2[sin(π/6-α)·cos(π/6) -cos(π/6-α)·sin(π/6)]
=2sin(π/6-α-π/6)
=2sin(-α)
=-2sinα
再问: 第一个等号后面2提出来后不应该是2[√3/2sin (π/6-α) -1/2cos(π/6-α)] 吗???
再答: √3 sin (π/6-α)-cos(π/6 -α)
=2[√3/2sin (π/6-α) -1/2cos(π/6-α)] 把√3/2误打为√3/1
=2[sin(π/6-α)·cos(π/6) -cos(π/6-α)·sin(π/6)]
=2sin(π/6-α-π/6)
=2sin(-α)
=-2sinα
=2[√3/1sin (π/6-α) -1/2cos(π/6-α)]
=2[sin(π/6-α)·cos(π/6) -cos(π/6-α)·sin(π/6)]
=2sin(π/6-α-π/6)
=2sin(-α)
=-2sinα
再问: 第一个等号后面2提出来后不应该是2[√3/2sin (π/6-α) -1/2cos(π/6-α)] 吗???
再答: √3 sin (π/6-α)-cos(π/6 -α)
=2[√3/2sin (π/6-α) -1/2cos(π/6-α)] 把√3/2误打为√3/1
=2[sin(π/6-α)·cos(π/6) -cos(π/6-α)·sin(π/6)]
=2sin(π/6-α-π/6)
=2sin(-α)
=-2sinα
化简:√3 sin〖(6/π〗-α)-cos〖(6/π〗-α)
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