2^log4底12减3^log9底27加5^log25底1/3的值
2^log4底12减3^log9底27加5^log25底1/3的值
2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
(1)log4 27乘以log25 8乘以log9 5 (2)(log4 3+log8 3)(log3 2+log9 2
(log2底5+log4底0.2)(log4底2+log25底0.4)的值是
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9)
(log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)=
计算3∧log9(lg2-1)∧2+5log25∧(lg0.5-2)∧2
(log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32
log4底3×log9底2-log0.5底32开4次根号 5上标1-log0.2底3
计算:(1/4)^log4^1/3-lg25-lg4-log9^27
[log4(3)/log4(8)][log3(2)log9(2)]
2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?`