How many real roots does the polynomial 2x^5+8x-7 have?
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How many real roots does the polynomial 2x^5+8x-7 have?
(A)None (B)One(C)Two(D)Three(E)Five
(A)None (B)One(C)Two(D)Three(E)Five
![How many real roots does the polynomial 2x^5+8x-7 have?](/uploads/image/z/7445788-52-8.jpg?t=How+many+real+roots+does+the+polynomial+2x%5E5%2B8x-7+have%3F)
不一定对
思路:2x^5+8x-7 =0
2x^5+8x=7
2x(x^4+8)=7
可以确定x只能是正值,解只能有一个
麻烦有正确答案后告知一下 哈哈
再问: 此题是选B,可为什么x只能是正值解就只能有一个呢
再答: x^4+8 一定是正值,2x(x^4+8)=7就相当于一元一次方程, 例如:6X=9 你说X解有几个? 如果答案中有具体的解释,我还是很期待看看他怎么解释的 哈哈
思路:2x^5+8x-7 =0
2x^5+8x=7
2x(x^4+8)=7
可以确定x只能是正值,解只能有一个
麻烦有正确答案后告知一下 哈哈
再问: 此题是选B,可为什么x只能是正值解就只能有一个呢
再答: x^4+8 一定是正值,2x(x^4+8)=7就相当于一元一次方程, 例如:6X=9 你说X解有几个? 如果答案中有具体的解释,我还是很期待看看他怎么解释的 哈哈
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