卡诺图化简,求详解 Y(A,B,C)=∑m(0,1,2,5,6,7) Y(A,B,C)=∑m(1,3,5,7)

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Y(A,B,C)=∑m(0,1,2,5,6,7)

Y=A'C'+AB+B'C或Y=A'B'+BC'+AC

Y(A,B,C)=∑m(1,3,5,7)=C

再问：您这种画法，我抄都不会抄，有简单易画的那种吗。可以列成化简法表达式吗？
再答：化简法表达式？如下这样吗：Y(A,B,C)=∑m(0,1,2,5,6,7)=∑m(0,2) +∑m(1,5) +∑m(6,7) =A'C'+B'C+ABY(A,B,C)=∑m(0,1,2,5,6,7)=∑m(0,1) +∑m(2,6) +∑m(5,7) =A'B'+BC'+AC
第二题修改一下图：原图两个1忘擦了，还少画一个1
Y(A,B,C)=∑m(1,3,5,7)=C

再问： Y(A,B,C)=∑m(1,3,5,7)=C 有化简法过程吗？
再答：这就是啊，不用分开，就一步得C
再答：不用谢

卡诺图化简,求详解 Y(A,B,C)=∑m(0,1,2,5,6,7) Y(A,B,C)=∑m(1,3,5,7) 用卡诺图化简Y(A,B,C)=∑m(0,1,2,3,6,7) Y(A,B,C,D)=∑m(0,1,2,5,6,7,8,9 用卡诺图法化简:Y(A,B,C,D)=∑m(0,2,5,7,8,10,13,15) 用卡诺图化简 F(A,B,C)=∑m(1,2,3,4,5,6) 用卡诺图化简法将函数化为最简与或表达式Y ( A,B,C ) = ∑m(0,1,2,5,6,7),如何作答, 1.卡诺图化简F(A,B,C,D)=∑m（0,1,2,3,5,7）用卡诺图化简逻辑函数F(A,B,C,)=∑m(0,1,2,4,5,7) 用卡诺图化简下列逻辑函数：Y(A,B,C,D)=∑m(2,3,5,7,8,9)+∑d(10,11,12,13,14,15 卡诺图化简F(A,B,C,D)=∑m(3,5,7,8,9,10,11)+∑m(0,1,2,13,14,15) 卡诺图化简 Y(A,B,C,D)=∑m(0,13,14,15)+∑d(1,2,3,9,10,11) 用卡诺图简化Y（A,B,C,D）=∑m（3,4,5,7,8,9,10,11）+∑d（0,1,2,13,14,15）将逻辑函数Y(A,B,C,D)=Σm(0,2,3,6,7,8)+Σd(4,10,11,12)用卡诺图化简