(1)化简,求值(x^2-2x/x^2-1)/[(x-1)-(2x-1/x+1)],x=1/2 (2)解方程:(3/x-
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(1)化简,求值
(x^2-2x/x^2-1)/[(x-1)-(2x-1/x+1)],x=1/2 (2)解方程:(3/x-1)+(2x/x+1)=2
(x^2-2x/x^2-1)/[(x-1)-(2x-1/x+1)],x=1/2 (2)解方程:(3/x-1)+(2x/x+1)=2
(x^2-2x/x^2-1)/[(x-1)-(2x-1/x+1)]
=(x^2-2x/x^2-1)/[(x^2-1)/(x+1)-(2x-1)/(x+1)]
=(x^2-2x/x^2-1)/[(x^2-1-2x+1)/(x+1)]
=(x^2-2x/x^2-1)*(x+1)/(x^2-2x)
1/(x-1)
当x=1/2时
原式=1/(1/2-1)
=-2
(2) (3/x-1)+(2x/x+1)=2
方程两边同乘以(x-1)(x+1)
得3(x+1)+2x(x-1)=2(x+1)(x-1)
化简之后结果为x=5
=(x^2-2x/x^2-1)/[(x^2-1)/(x+1)-(2x-1)/(x+1)]
=(x^2-2x/x^2-1)/[(x^2-1-2x+1)/(x+1)]
=(x^2-2x/x^2-1)*(x+1)/(x^2-2x)
1/(x-1)
当x=1/2时
原式=1/(1/2-1)
=-2
(2) (3/x-1)+(2x/x+1)=2
方程两边同乘以(x-1)(x+1)
得3(x+1)+2x(x-1)=2(x+1)(x-1)
化简之后结果为x=5
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