[(x²+y²)-(x-y)²+2y(x-y)]÷1/2
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
(x-2y)²+(2x-4y)(x+y)+(x+y)²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(x-y)的四次方(x-y)-2(x-y)²(y-x)³等于?
先化简再求值:(x-2y)²-(x+2y)(x-2y)-(x-3y)(x-y).其中x²+9y
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
{(x-y)²+(x+y)(x-y)}÷2x
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
[(x²+y²)-(x-y)²+2y(x-y)]÷1/2
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]