arctan1/2+arctan1/5+arctan1/3

来源：学生作业帮编辑：百度作业网作业帮分类：综合作业时间：2024/07/07 18:46:38

tana1=1/5,tana2=1/3 tana3=1/2 上式=a1+a2+a3
tan(a1+a2)=(tana1+tana2)/(1-tana1tana2)=4/7 a1+a2=arctan4/7 tan(a1+a2+a3)=[tan(a1+a2)+tana3]/(1-tan(a1+a2)tana3) =3/2 所以a1+a2+a3 =arctan(3/2)

arctan1/2+arctan1/5+arctan1/3 arctan1/2+arctan1/5+arctan1/8= arctan1/3+arctan1/2+arctan1=几, arctan1/3+arctan1/5+arctan1/7+arctan1/8 求证arctan1/2+arctan1/5+arctan1/8=pai/4 arctan1/2+arctan1/3 解答题证明arctan1/2+arctan1/3=45° tan（arctan1/5+arctan3) A=arctan1/2 求arctan1/3+arctan(-2)的值 arctan1/3+arctan(-2)的值为求arctan1/3+arctan(-2)的值.